Solution
Solution
Solution steps
Treat as a constant
Take the constant out:
Apply exponent rule:
Apply the chain rule:
Simplify
Popular Examples
y^{''}-y^'-6y=e^{-2x}tangent of f(x)=(2x-3)/(2x+5),\at x=-1tangent of limit as x approaches 0 of 3x^2-4x+5integral from 1 to sqrt(2 of)x5^{x^2}integral of e^{-jwt}
Frequently Asked Questions (FAQ)
What is the d/(dy)(x/(x^2+y^2)) ?
The d/(dy)(x/(x^2+y^2)) is -(2xy)/((x^2+y^2)^2)What is the first d/(dy)(x/(x^2+y^2)) ?
The first d/(dy)(x/(x^2+y^2)) is -(2xy)/((x^2+y^2)^2)