What is the derivative of ln(e^{7x}) ?

The derivative of ln(e^{7x}) is 7

What is the first derivative of ln(e^{7x}) ?

The first derivative of ln(e^{7x}) is 7

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\frac{d}{d x} (ln (e^{7 x}))

7

Solution steps

\frac{d}{d x} (ln (e^{7 x}))

Simplify

ln (e^{7 x}) : 7 x

= \frac{d}{d x} (7 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 7 \cdot 1

Simplify

= 7

x \to - 3 lim (- 1)

\int \frac{1}{( x + 4 ) x ^{2} + 8 x} d x

b e^{x}

\int \frac{1}{( x ^{2} + 2 ) ^{2}} d x

\int_{1}^{32} x^{- (\frac{8}{5})} d x

What is the derivative of ln(e^{7x}) ?
The derivative of ln(e^{7x}) is 7
What is the first derivative of ln(e^{7x}) ?
The first derivative of ln(e^{7x}) is 7