What is the solution for (dy)/(dx)=10+40x+10y+40xy ?

The solution for (dy)/(dx)=10+40x+10y+40xy is y=-1+c_{1}e^{10(2x^2+x)}

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(dy)/(dx)=10+40x+10y+40xy

\frac{d y}{d x} = 10 + 40 x + 10 y + 40 x y

y = - 1 + c_{1} e^{10 (2 x^{2} + x)}

Solution steps

\frac{d y}{d x} = 10 + 40 x + 10 y + 40 x y

Solve linear ODE:

y = - 1 + c_{1} e^{10 (2 x^{2} + x)}

y = - 1 + c_{1} e^{10 (2 x^{2} + x)}

\frac{d}{d x} (π x^{3})

\int tan (x) (6 cos (x) - 6 sec (x)) d x

y = \frac{1}{x - 1}

\int \frac{1}{2 + x} d x

y = cot (7 x - 3)

What is the solution for (dy)/(dx)=10+40x+10y+40xy ?
The solution for (dy)/(dx)=10+40x+10y+40xy is y=-1+c_{1}e^{10(2x^2+x)}