What is the integral of (\sqrt[4]{x^3}) ?

The integral of (\sqrt[4]{x^3}) is 4/7 x^{7/4}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (\sqrt[4]{x^3})

\int (4 x^{3}) d x

\frac{4}{7} x^{\frac{7}{4}} + C

Solution steps

\int 4 x^{3} d x

4 x^{3} = x^{\frac{3}{4}},

assuming

x \geq 0

= \int x^{\frac{3}{4}} d x

Apply the Power Rule

: \frac{4}{7} x^{\frac{7}{4}}

= \frac{4}{7} x^{\frac{7}{4}}

Add a constant to the solution

= \frac{4}{7} x^{\frac{7}{4}} + C

\int sinh (x) cosh^{2} (x) d x

\frac{0.25}{s}

\frac{1}{x ^{2} + 0.0184}

\int \frac{10}{( x - 1 ) ( x ^{2} - 9 )} d x

x \to 0 - lim (8 - x^{2})

What is the integral of (\sqrt[4]{x^3}) ?
The integral of (\sqrt[4]{x^3}) is 4/7 x^{7/4}+C