What is the integral of cos(In(x)) ?

The integral of cos(In(x)) is 1/(In)sin(Inx)+C

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integral of cos(In(x))

\int cos (I n (x)) d x

\frac{1}{I n} sin (I n x) + C

Solution steps

\int cos (I n x) d x

Apply u-substitution

: \int \frac{cos ( u )}{I n} d u

= \int \frac{cos ( u )}{I n} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{I n} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{I n} sin (u)

Substitute back

u = I n x

= \frac{1}{I n} sin (I n x)

Add a constant to the solution

= \frac{1}{I n} sin (I n x) + C

\frac{d}{d x} (\frac{1}{( 1 - 2 x ) ^{2}})

\frac{d}{d x} (\frac{x ^{2} - 64}{x ^{2} + 64})

x \to 0 lim (\frac{\frac{4}{1 + x} - 4}{x})

\frac{\partial}{\partial x} (\frac{14 x}{7 x ^{2} + y ^{2} + 2})

\int_{0}^{1} \frac{1}{x + 2} d x

What is the integral of cos(In(x)) ?
The integral of cos(In(x)) is 1/(In)sin(Inx)+C