What is the integral from-infinity to 0 of 1/(4-9x) ?

The integral from-infinity to 0 of 1/(4-9x) is diverges

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integral from-infinity to 0 of 1/(4-9x)

\int_{- \infty}^{0} \frac{1}{4 - 9 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{4 - 9 x} d x

Compute the indefinite integral:

\int \frac{1}{4 - 9 x} d x = - \frac{1}{9} ln ∣ 4 - 9 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{4 - 9 x} d x =

diverges

= diverges

f (x) = x^{2} - 4

\int \frac{x ^{4}}{x ^{2} - 4} d x

\frac{d}{d x} (ln (18 - x^{2}))

\frac{\partial}{\partial x} (2 \cdot (y - 2)^{3} \cdot (x - 6))

(0.3) (2.7)

What is the integral from-infinity to 0 of 1/(4-9x) ?
The integral from-infinity to 0 of 1/(4-9x) is diverges