What is the derivative of 2/(9x^3) ?

The derivative of 2/(9x^3) is -2/(3x^4)

What is the first derivative of 2/(9x^3) ?

The first derivative of 2/(9x^3) is -2/(3x^4)

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\frac{d}{d x} (\frac{2}{9 x ^{3}})

- \frac{2}{3 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{2}{9 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{9} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{2}{9} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{9} (- 3 x^{- 3 - 1})

Simplify

\frac{2}{9} (- 3 x^{- 3 - 1}) : - \frac{2}{3 x ^{4}}

= - \frac{2}{3 x ^{4}}

d y = x^{2} sin (8 x) d x

\frac{\partial}{\partial y} (x^{2} y^{3} sin (x - 2 y))

x \to 7 lim (x + 6)

y^{^{'}} = \frac{x}{14 y}

\int_{\frac{3 π}{2}}^{2 π} - 4 sin (x) d x

What is the derivative of 2/(9x^3) ?
The derivative of 2/(9x^3) is -2/(3x^4)
What is the first derivative of 2/(9x^3) ?
The first derivative of 2/(9x^3) is -2/(3x^4)