What is (\partial)/(\partial x)(x(150y+60z+240t)) ?

The answer to (\partial)/(\partial x)(x(150y+60z+240t)) is 150y+60z+240t

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(\partial)/(\partial x)(x(150y+60z+240t))

\frac{\partial}{\partial x} (x (150 y + 60 z + 240 t))

150 y + 60 z + 240 t

Solution steps

\frac{\partial}{\partial x} (x (150 y + 60 z + 240 t))

Treat

y, z, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (150 y + 60 z + 240 t) \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= (150 y + 60 z + 240 t) \cdot 1

Simplify

= 150 y + 60 z + 240 t

(x^{4} + 3 x^{2}) (- x^{2} + 6 x + 7)

(\frac{x}{3 x + 4 ln ( x )})^{^{'}}

\frac{\partial}{\partial x} (5 - 3 x)

f (x) = sin^{3} (2 x)

\frac{s - 10}{s ^{3} ( s + 2.5 ) ^{2}}

What is (\partial)/(\partial x)(x(150y+60z+240t)) ?
The answer to (\partial)/(\partial x)(x(150y+60z+240t)) is 150y+60z+240t