What is the integral from-3 to 0 of 9/(9x+4) ?

The integral from-3 to 0 of 9/(9x+4) is diverges

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integral from-3 to 0 of 9/(9x+4)

\int_{- 3}^{0} \frac{9}{9 x + 4} d x

diverges

Solution steps

\int_{- 3}^{0} \frac{9}{9 x + 4} d x

Find undefined (singularity) points:

x = - \frac{4}{9}

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 3}^{- \frac{4}{9}} \frac{9}{9 x + 4} d x + \int_{- \frac{4}{9}}^{0} \frac{9}{9 x + 4} d x

\int_{- 3}^{- \frac{4}{9}} \frac{9}{9 x + 4} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int \frac{20}{1 + x ^{2}} d x

n = 1 \sum \infty \frac{1}{ln ( n )}

\frac{\partial}{\partial y} (arctan (x y^{2}))

\int 2 t e^{2 t} d t

x \to 0 - lim (\frac{3}{e ^{x} + 1})

What is the integral from-3 to 0 of 9/(9x+4) ?
The integral from-3 to 0 of 9/(9x+4) is diverges