What is (\partial ^2)/(\partial x\partial y)(xye^{-7y}) ?

The answer to (\partial ^2)/(\partial x\partial y)(xye^{-7y}) is -7e^{-7y}y+e^{-7y}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial ^2)/(\partial x\partial y)(xye^{-7y})

\frac{\partial ^{2}}{\partial x \partial y} (x y e^{- 7 y})

- 7 e^{- 7 y} y + e^{- 7 y}

Solution steps

\frac{\partial ^{2}}{\partial x \partial y} (x y e^{- 7 y})

\frac{\partial}{\partial x} (x y e^{- 7 y}) = e^{- 7 y} y

= \frac{\partial}{\partial y} (e^{- 7 y} y)

\frac{\partial}{\partial y} (e^{- 7 y} y) = - 7 e^{- 7 y} y + e^{- 7 y}

= - 7 e^{- 7 y} y + e^{- 7 y}

\int \frac{x - 2}{( x ^{2} - 4 x + 5 ) ^{2}} d x

(cos (4 x))^{^{'}}

\int_{- 2}^{3} \frac{48}{x ^{4}} d x

\int_{0}^{4 π} t^{2} + 5 d t

What is (\partial ^2)/(\partial x\partial y)(xye^{-7y}) ?
The answer to (\partial ^2)/(\partial x\partial y)(xye^{-7y}) is -7e^{-7y}y+e^{-7y}