What is the tangent of f(x)=sqrt(7x+11),(2,5) ?

The tangent of f(x)=sqrt(7x+11),(2,5) is y= 7/10 x+18/5

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tangent of f(x)=sqrt(7x+11),(2,5)

tangent of

f (x) = 7 x + 11, (2, 5)

y = \frac{7}{10} x + \frac{18}{5}

Solution steps

Find the slope of

f (x) = 7 x + 11 : \frac{df ( x )}{d x} = \frac{7}{2 7 x + 11}

Compute the slope of

f (x) = 7 x + 11

(2, 5) : m = \frac{7}{10}

Find the line with slope m=

\frac{7}{10}

and passing through

(2, 5) : y = \frac{7}{10} x + \frac{18}{5}

y = \frac{7}{10} x + \frac{18}{5}

y^{^{''}} - 4 y = e^{x} cos (x), y (0) = 0.7, y^{^{'}} (0) = - 1.5

\frac{d y}{d t} = y^{2}

f (x) = ln (6 x)

\int e^{2 x} cos (5 x) d x

\frac{d y}{d x} + y = cos (x)

What is the tangent of f(x)=sqrt(7x+11),(2,5) ?
The tangent of f(x)=sqrt(7x+11),(2,5) is y= 7/10 x+18/5