What is the derivative of (e^x)/(x-1) ?

The derivative of (e^x)/(x-1) is (e^xx-2e^x)/((x-1)^2)

What is the first derivative of (e^x)/(x-1) ?

The first derivative of (e^x)/(x-1) is (e^xx-2e^x)/((x-1)^2)

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derivative of

\frac{e ^{x}}{x - 1}

\frac{e ^{x} x - 2 e ^{x}}{( x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{x - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} ) ( x - 1 ) - \frac{d}{d x} ( x - 1 ) e ^{x}}{( x - 1 ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x - 1) = 1

= \frac{e ^{x} ( x - 1 ) - 1 \cdot e ^{x}}{( x - 1 ) ^{2}}

Simplify

\frac{e ^{x} ( x - 1 ) - 1 \cdot e ^{x}}{( x - 1 ) ^{2}} : \frac{e ^{x} x - 2 e ^{x}}{( x - 1 ) ^{2}}

= \frac{e ^{x} x - 2 e ^{x}}{( x - 1 ) ^{2}}

\int 3 cos (3 t) d t

x \to 2 lim (\frac{2 x - 3}{x + 1})

(3, 1), (- 2, - 2)

n = 0 \sum \infty (n x)^{n}

\int \frac{4}{3} x^{3} d x

What is the derivative of (e^x)/(x-1) ?
The derivative of (e^x)/(x-1) is (e^xx-2e^x)/((x-1)^2)
What is the first derivative of (e^x)/(x-1) ?
The first derivative of (e^x)/(x-1) is (e^xx-2e^x)/((x-1)^2)