What is the derivative of 15cos(3t) ?

The derivative of 15cos(3t) is -45sin(3t)

What is the first derivative of 15cos(3t) ?

The first derivative of 15cos(3t) is -45sin(3t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

15 cos (3 t)

- 45 sin (3 t)

Solution steps

\frac{d}{d t} (15 cos (3 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 15 \frac{d}{d t} (cos (3 t))

Apply the chain rule:

- sin (3 t) \frac{d}{d t} (3 t)

= - sin (3 t) \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= 15 (- sin (3 t) \cdot 3)

Simplify

= - 45 sin (3 t)

\frac{5 d x}{d t} = x^{2}

n = 0 \sum \infty q^{2 n}

x \to 0 lim (\frac{1}{x + 1})

\frac{d}{d x} (x^{0.5} y^{0.5})

\frac{\partial}{\partial x} (3 e^{3 x + 4 y} cos (5 z))

What is the derivative of 15cos(3t) ?
The derivative of 15cos(3t) is -45sin(3t)
What is the first derivative of 15cos(3t) ?
The first derivative of 15cos(3t) is -45sin(3t)