What is area x=-2,x=1,y=2x^2+12,y=0 ?

The answer to area x=-2,x=1,y=2x^2+12,y=0 is 42

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area x=-2,x=1,y=2x^2+12,y=0

area

x = - 2, x = 1, y = 2 x^{2} + 12, y = 0

42

Solution steps

Apply the area formula:

\int_{- 2}^{1} 2 x^{2} + 12 d x

Solve

\int_{- 2}^{1} 2 x^{2} + 12 d x : 42

The area is:

= 42

f (x) = 5 x + 11, (5, 6)

f (x) = \frac{3}{x ^{2}}

f (x) = 3 (x^{3} - x^{2})

\int (ln (x^{3})) d x

\int \frac{1}{2 x - 2} d x

What is area x=-2,x=1,y=2x^2+12,y=0 ?
The answer to area x=-2,x=1,y=2x^2+12,y=0 is 42