What is (\partial)/(\partial x)(x^2+y^2) ?

The answer to (\partial)/(\partial x)(x^2+y^2) is 2x

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(\partial)/(\partial x)(x^2+y^2)

\frac{\partial}{\partial x} (x^{2} + y^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 2 x + 0

Simplify

= 2 x

\int sech (x) d x

7 x - 7 x

\frac{d}{d x} ((\frac{4 x + 1}{2 - 5 x})^{\frac{1}{3}})

f (x) = 5 x^{2} cos (x) - 4 x

What is (\partial)/(\partial x)(x^2+y^2) ?
The answer to (\partial)/(\partial x)(x^2+y^2) is 2x