What is the integral of 7(1+tan^2(a)) ?

The integral of 7(1+tan^2(a)) is 7tan(a)+C

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integral of 7(1+tan^2(a))

\int 7 (1 + tan^{2} (a)) d a

7 tan (a) + C

Solution steps

\int 7 (1 + tan^{2} (a)) d a

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int 1 + tan^{2} (a) d a

Rewrite using trig identities

= 7 \cdot \int sec^{2} (a) d a

Use the common integral:

\int sec^{2} (a) d a = tan (a)

= 7 tan (a)

Add a constant to the solution

= 7 tan (a) + C

h (x) = \frac{8}{x} - \frac{2}{x ^{3}} + \frac{1}{x ^{4}}

y^{^{''}} - 14 y^{^{'}} + 85 y = 0

\frac{\partial}{\partial x} (\frac{4}{x})

- \frac{12}{s ^{5}}

\frac{2}{s ^{4}}

What is the integral of 7(1+tan^2(a)) ?
The integral of 7(1+tan^2(a)) is 7tan(a)+C