What is the d/(dt)(2cos(t)) ?

The d/(dt)(2cos(t)) is -2sin(t)

What is the first d/(dt)(2cos(t)) ?

The first d/(dt)(2cos(t)) is -2sin(t)

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\frac{d}{d t} (2 cos (t))

- 2 sin (t)

Solution steps

\frac{d}{d t} (2 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= 2 (- sin (t))

Simplify

= - 2 sin (t)

\frac{\partial}{\partial z} (ln (z))

\frac{\partial}{\partial x} (2 y^{7} + 8 y^{7} x^{7})

f (x) = cos (x) + sin (x)

\frac{d x}{d y} = 4 (x^{2} + 1), x (\frac{π}{4}) = 1

t (\frac{d y}{d t}) = t^{3} + 22 t^{3} y