What is the solution for x(dy)/(dx)+y=y^2x^2ln(x) ?

The solution for x(dy)/(dx)+y=y^2x^2ln(x) is y= 1/(x(-xln(x)+x+c_{1))}

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x(dy)/(dx)+y=y^2x^2ln(x)

x \frac{d y}{d x} + y = y^{2} x^{2} ln (x)

y = \frac{1}{x ( - x ln ( x ) + x + c _{1} )}

Solution steps

x \frac{d y}{d x} + y = y^{2} x^{2} ln (x)

Solve Bernoulli ODE:

y = \frac{1}{x ( - x ln ( x ) + x + c _{1} )}

y = \frac{1}{x ( - x ln ( x ) + x + c _{1} )}

\int \frac{y}{x ^{2} + y ^{2}} d x

\frac{2 s + 12}{( s ^{2} + 2 s + 5 )}

\frac{d x}{d t} = sin (t)

x \to \infty lim (5 - x)

\frac{d}{d x} (sin^{2} (π x))

What is the solution for x(dy)/(dx)+y=y^2x^2ln(x) ?
The solution for x(dy)/(dx)+y=y^2x^2ln(x) is y= 1/(x(-xln(x)+x+c_{1))}