What is (\partial)/(\partial y)(7sin(xy)) ?

The answer to (\partial)/(\partial y)(7sin(xy)) is 7cos(xy)x

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(\partial)/(\partial y)(7sin(xy))

\frac{\partial}{\partial y} (7 sin (x y))

7 cos (x y) x

Solution steps

\frac{\partial}{\partial y} (7 sin (x y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{\partial}{\partial y} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial y} (x y)

= cos (x y) \frac{\partial}{\partial y} (x y)

\frac{\partial}{\partial y} (x y) = x

= 7 cos (x y) x

\frac{\partial}{\partial x} (3 x e^{5 x y})

x \to - 4 lim (x)

\int \frac{x ^{2}}{( 1 + 2 x ) ^{\frac{1}{3}}} d x

\frac{\partial}{\partial y} (e^{x y} y^{2} + \frac{x}{y})

\frac{\partial}{\partial r} (r^{2} + s^{2})

What is (\partial)/(\partial y)(7sin(xy)) ?
The answer to (\partial)/(\partial y)(7sin(xy)) is 7cos(xy)x