What is the derivative of x^3+5x+7 ?

The derivative of x^3+5x+7 is 3x^2+5

What is the first derivative of x^3+5x+7 ?

The first derivative of x^3+5x+7 is 3x^2+5

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\frac{d}{d x} (x^{3} + 5 x + 7)

3 x^{2} + 5

Solution steps

\frac{d}{d x} (x^{3} + 5 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (5 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (7) = 0

= 3 x^{2} + 5 + 0

Simplify

= 3 x^{2} + 5

e^{- t} + 2 e^{- 2 t} + t e^{- 3 t}

\int \frac{5 cosh ( x )}{x} d x

n = 0 \sum \infty \frac{n}{2 n ^{2} + 1}

x \to 4 lim (\frac{7}{x - 5})

\frac{d}{d x} ((x^{2} - 5 x + 8) (3 x^{2} - 2))

What is the derivative of x^3+5x+7 ?
The derivative of x^3+5x+7 is 3x^2+5
What is the first derivative of x^3+5x+7 ?
The first derivative of x^3+5x+7 is 3x^2+5