What is the derivative of 8sin(xcos(x)) ?

The derivative of 8sin(xcos(x)) is 8cos(2x)

What is the first derivative of 8sin(xcos(x)) ?

The first derivative of 8sin(xcos(x)) is 8cos(2x)

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\frac{d}{d x} (8 sin (x) cos (x))

8 cos (2 x)

Solution steps

\frac{d}{d x} (8 sin (x) cos (x))

Simplify

8 sin (x) cos (x) : 4 sin (2 x)

= \frac{d}{d x} (4 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 4 cos (2 x) \cdot 2

Simplify

= 8 cos (2 x)

\int x^{5} sin (x) d x

\int \frac{4 - x ^{2}}{x ^{2}} d x

\int cos (x) cos^{3} (sin (x)) d x

f (x) = 3 x ln (5 x) - 3 x

\int x^{3} e^{- 4 x} d x

What is the derivative of 8sin(xcos(x)) ?
The derivative of 8sin(xcos(x)) is 8cos(2x)
What is the first derivative of 8sin(xcos(x)) ?
The first derivative of 8sin(xcos(x)) is 8cos(2x)