What is area y=x^4+x^3,y=x^4+x^2+6x ?

The answer to area y=x^4+x^3,y=x^4+x^2+6x is 253/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x^4+x^3,y=x^4+x^2+6x

area

y = x^{4} + x^{3}, y = x^{4} + x^{2} + 6 x

\frac{253}{12}

Decimal

21.08333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} x^{4} + x^{3} - (x^{4} + x^{2} + 6 x) d x

Solve

\int_{- 2}^{3} x^{4} + x^{3} - (x^{4} + x^{2} + 6 x) d x : \frac{253}{12}

The area is:

= \frac{253}{12}

\frac{d}{d x} (e^{x} sin (4 x))

\frac{d}{d x} (A e^{4 x})

\frac{\partial}{\partial v} (2 u + v)

ln (7 x + 9)

\int \frac{( x )}{16 x ^{4} - 1} d x

What is area y=x^4+x^3,y=x^4+x^2+6x ?
The answer to area y=x^4+x^3,y=x^4+x^2+6x is 253/12