What is the tangent of f(x)=12(x-1/x)^2,\at x=2 ?

The tangent of f(x)=12(x-1/x)^2,\at x=2 is y=45x-63

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tangent of f(x)=12(x-1/x)^2,\at x=2

tangent of

f (x) = 12 (x - \frac{1}{x})^{2}, at x = 2

y = 45 x - 63

Solution steps

Find the tangent point:

(2, 27)

Find the slope of

f (x) = 12 (x - \frac{1}{x})^{2} : \frac{df ( x )}{d x} = 12 (2 x - \frac{2}{x ^{3}})

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 45

Find the line with slope m=

45

and passing through

(2, 27) : y = 45 x - 63

y = 45 x - 63

\int \frac{( e ^{x} + e ^{- x} )}{2} d x

\frac{ln ( x )}{2 x} + \frac{1}{x}

x \to 0 lim (\frac{2 x}{x})

x \to - 4 - lim (\frac{2}{x ^{2} - 16})

\frac{d y}{d x} = \frac{( e ^{x} - e ^{- x} )}{3 + y}

What is the tangent of f(x)=12(x-1/x)^2,\at x=2 ?
The tangent of f(x)=12(x-1/x)^2,\at x=2 is y=45x-63