What is the limit as x approaches-3 of (x+3)/(x^2-9) ?

The limit as x approaches-3 of (x+3)/(x^2-9) is -1/6

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limit as x approaches-3 of (x+3)/(x^2-9)

x \to - 3 lim (\frac{x + 3}{x ^{2} - 9})

- \frac{1}{6}

Decimal

- 0.16666 \dots

Solution steps

x \to - 3 lim (\frac{x + 3}{x ^{2} - 9})

Simplify

\frac{x + 3}{x ^{2} - 9} : \frac{1}{x - 3}

= x \to - 3 lim (\frac{1}{x - 3})

Plug in the value

x = - 3

= \frac{1}{- 3 - 3}

Simplify

= - \frac{1}{6}

f (x) = 2 x e^{x}

\frac{d}{d x} (\frac{x e ^{x}}{x + 1})

\int (x^{2} - 3 x + 5) e^{x} d x

[x + (x + sin (2) (x))^{7}]^{3}

7 x - x^{2}

What is the limit as x approaches-3 of (x+3)/(x^2-9) ?
The limit as x approaches-3 of (x+3)/(x^2-9) is -1/6