What is the tangent of 2x^2+x-1,\at x=1 ?

The tangent of 2x^2+x-1,\at x=1 is y=5x-3

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tangent of 2x^2+x-1,\at x=1

tangent of

2 x^{2} + x - 1, at x = 1

y = 5 x - 3

Solution steps

Find the tangent point:

(1, 2)

Find the slope of

y = 2 x^{2} + x - 1 : \frac{d y}{d x} = 4 x + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

Find the line with slope m=

5

and passing through

(1, 2) : y = 5 x - 3

y = 5 x - 3

\int \frac{x ^{2}}{( 10 - x ) ( 10 + x )} d x

\int sin^{3} (x co) s^{10} x d x

\frac{d}{d x} (\frac{1}{a + b x + c x ^{2}} + 0.003)

\frac{\partial}{\partial y} (cos (2 x) y)

\frac{d y}{d x} = \frac{x - 1}{y + 2}

What is the tangent of 2x^2+x-1,\at x=1 ?
The tangent of 2x^2+x-1,\at x=1 is y=5x-3