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Popular >

xy^'+y=y^{-2}

Solution

x y^{^{'}} + y = y^{- 2}

Solution

y = \frac{3 - c _{1} + x ^{3}}{x}

Solution steps

x y^{'} (x) + y = y^{- 2}

Solve separable ODE:

y = \frac{3 - c _{1} + x ^{3}}{x}

y = \frac{3 - c _{1} + x ^{3}}{x}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=y^{-2} ?
The solution for xy^'+y=y^{-2} is y=(\sqrt[3]{-c_{1}+x^3})/x