What is (\partial)/(\partial x)(ysin(x)y) ?

The answer to (\partial)/(\partial x)(ysin(x)y) is y^2cos(x)

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(\partial)/(\partial x)(ysin(x)y)

\frac{\partial}{\partial x} (y sin (x) y)

y^{2} cos (x)

Solution steps

\frac{\partial}{\partial x} (y sin (x) y)

Simplify

y sin (x) y : y^{2} sin (x)

= \frac{\partial}{\partial x} (y^{2} sin (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= y^{2} cos (x)

f (x) = \frac{2 x + 3}{4}

\int \frac{e ^{- 2 x}}{x} d x

\frac{\partial}{\partial x} ((x - 1)^{2} + (y - 1)^{2})

\int_{- 1}^{1} \frac{tan ( x )}{1 + x ^{4}} d x

\int_{- \infty}^{0} \frac{1}{2 - 8 x} d x

What is (\partial)/(\partial x)(ysin(x)y) ?
The answer to (\partial)/(\partial x)(ysin(x)y) is y^2cos(x)