What is (\partial)/(\partial x)(4x^2+3y^2-4xy+x) ?

The answer to (\partial)/(\partial x)(4x^2+3y^2-4xy+x) is 8x+1-4y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4x^2+3y^2-4xy+x)

\frac{\partial}{\partial x} (4 x^{2} + 3 y^{2} - 4 x y + x)

8 x + 1 - 4 y

Solution steps

\frac{\partial}{\partial x} (4 x^{2} + 3 y^{2} - 4 x y + x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{2}) + \frac{\partial}{\partial x} (3 y^{2}) - \frac{\partial}{\partial x} (4 x y) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (4 x^{2}) = 8 x

\frac{\partial}{\partial x} (3 y^{2}) = 0

\frac{\partial}{\partial x} (4 x y) = 4 y

\frac{\partial}{\partial x} (x) = 1

= 8 x + 0 - 4 y + 1

Simplify

= 8 x + 1 - 4 y

\frac{d}{d x} (e^{t a n (3 x)})

\frac{d}{d t} (\frac{t}{2})

\int \frac{12}{x ^{3} + 8} d x

t^{3} + 4 t^{2} + 5

\frac{d}{d x} (6 e^{x} + 2)

What is (\partial)/(\partial x)(4x^2+3y^2-4xy+x) ?
The answer to (\partial)/(\partial x)(4x^2+3y^2-4xy+x) is 8x+1-4y