What is the integral of e^{-x}sin(3x) ?

The integral of e^{-x}sin(3x) is -(3e^{-x}cos(3x))/(10)-(e^{-x}sin(3x))/(10)+C

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integral of e^{-x}sin(3x)

\int e^{- x} sin (3 x) d x

- \frac{3 e ^{- x} cos ( 3 x )}{10} - \frac{e ^{- x} sin ( 3 x )}{10} + C

Solution steps

\int e^{- x} sin (3 x) d x

Apply Integration By Parts

: - \frac{1}{3} e^{- x} cos (3 x) - \int \frac{1}{3} e^{- x} cos (3 x) d x

= - \frac{1}{3} e^{- x} cos (3 x) - \int \frac{1}{3} e^{- x} cos (3 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{3} e^{- x} cos (3 x) - \frac{1}{3} \cdot \int e^{- x} cos (3 x) d x

Apply Integration By Parts

: \frac{1}{3} e^{- x} sin (3 x) - \int - \frac{1}{3} e^{- x} sin (3 x) d x

= - \frac{1}{3} e^{- x} cos (3 x) - \frac{1}{3} (\frac{1}{3} e^{- x} sin (3 x) - \int - \frac{1}{3} e^{- x} sin (3 x) d x)

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{3} e^{- x} cos (3 x) - \frac{1}{3} (\frac{1}{3} e^{- x} sin (3 x) - (- \frac{1}{3} \cdot \int e^{- x} sin (3 x) d x))

Therefore

\int e^{- x} sin (3 x) d x = - \frac{1}{3} e^{- x} cos (3 x) - \frac{1}{3} (\frac{1}{3} e^{- x} sin (3 x) - (- \frac{1}{3} \cdot \int e^{- x} sin (3 x) d x))

Isolate

\int e^{- x} sin (3 x) d x

= - \frac{3 e ^{- x} cos ( 3 x )}{10} - \frac{e ^{- x} sin ( 3 x )}{10}

Add a constant to the solution

= - \frac{3 e ^{- x} cos ( 3 x )}{10} - \frac{e ^{- x} sin ( 3 x )}{10} + C

h \to 0 lim ((x + h) 3 - x^{3} h)

\int (1 + y^{3})^{2} d y

y = \frac{3 + x f ( x )}{x}

x \to - \infty lim (- 1)

\int_{- 3}^{4} ∣ x ∣ d x

What is the integral of e^{-x}sin(3x) ?
The integral of e^{-x}sin(3x) is -(3e^{-x}cos(3x))/(10)-(e^{-x}sin(3x))/(10)+C