What is (\partial)/(\partial x)(x-xy) ?

The answer to (\partial)/(\partial x)(x-xy) is 1-y

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(\partial)/(\partial x)(x-xy)

\frac{\partial}{\partial x} (x - x y)

1 - y

Solution steps

\frac{\partial}{\partial x} (x - x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x y) = y

= 1 - y

\frac{d}{d x} (- 16 cos (4 x))

\frac{d}{d x} (x + \frac{4}{x} + 4)

\int \frac{25 + x ^{2}}{x} d x

\frac{\partial}{\partial y} (x 1 + y^{7})

f (x) = \frac{6 x}{x + 2}, at x = 4

What is (\partial)/(\partial x)(x-xy) ?
The answer to (\partial)/(\partial x)(x-xy) is 1-y