What is the integral of (-ln(x))/x ?

The integral of (-ln(x))/x is -(ln^2(x))/2+C

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integral of (-ln(x))/x

\int \frac{- ln ( x )}{x} d x

- \frac{ln ^{2} ( x )}{2} + C

Solution steps

\int \frac{- ln ( x )}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{ln ( x )}{x} d x

Apply u-substitution

: \int u d u

= - \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= - \frac{u ^{2}}{2}

Substitute back

u = ln (x)

= - \frac{ln ^{2} ( x )}{2}

Add a constant to the solution

= - \frac{ln ^{2} ( x )}{2} + C

y = c e^{x}

\int \frac{1}{cot ( y )} d y

x \to 0 - lim (x^{2} - 1)

\int \frac{x ^{2} - 3 x + 2}{x - 1} d x

\int \frac{x ^{2} - 3 x - 7}{( 2 x + 3 ) ( x + 1 ) ^{2}} d x

What is the integral of (-ln(x))/x ?
The integral of (-ln(x))/x is -(ln^2(x))/2+C