What is area y=x^4-x^2,y^2=x^2 ?

The answer to area y=x^4-x^2,y^2=x^2 is No Solution

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area y=x^4-x^2,y^2=x^2

area

y = x^{4} - x^{2}, y^{2} = x^{2}

No Solution

Solution steps

Isolate

y

for

y^{2} = x^{2} : y = x, y = - x

f_{1} (x) = x^{4} - x^{2}

f_{2} (x) = x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x^{4} - x^{2} = x : x = 0, x \approx 1.32471 \dots

x^{4} - x^{2} = - x : x = 0, x \approx - 1.32471 \dots

x = - x : x = 0

Curves not bounded

= No Solution

y^{^{''}} - 2 y^{^{'}} + \frac{53}{4} y = 0

x \to 0 - lim (\frac{cos ( x )}{x})

\frac{d y}{d x} = \frac{( 2 x + sec ^{2} ( x ) )}{2 y}

x \to 2 + lim (\frac{x - 13}{- x + 2})

(t + 1)^{\frac{2}{3}} (2 t^{2} - 1)^{3}

What is area y=x^4-x^2,y^2=x^2 ?
The answer to area y=x^4-x^2,y^2=x^2 is No Solution