What is area y=cos(x),y=2-cos(x),0<= x<= 2pi ?

The answer to area y=cos(x),y=2-cos(x),0<= x<= 2pi is 4pi

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area y=cos(x),y=2-cos(x),0<= x<= 2pi

area

y = cos (x), y = 2 - cos (x), 0 \leq x \leq 2 π

4 π

Decimal

12.56637 \dots

Solution steps

Apply the area formula:

\int_{0}^{2 π} ∣ cos (x) - (2 - cos (x)) ∣ d x

Solve

\int_{0}^{2 π} ∣ cos (x) - (2 - cos (x)) ∣ d x : 4 π

The area is:

= 4 π

\frac{d}{d y} (5 x + 4 y)

\int_{- 1}^{4} (2 x + 4)^{2} d x

\frac{d}{d x} (ln (\frac{2 x}{3}))

\frac{d}{d x} (\frac{1}{( 1 - x ) ^{4}})

\int \frac{cos ( x )}{( sin ( x ) ) ^{2}} d x

What is area y=cos(x),y=2-cos(x),0<= x<= 2pi ?
The answer to area y=cos(x),y=2-cos(x),0<= x<= 2pi is 4pi