What is the derivative of sin^2(2x^3+2x^2) ?

The derivative of sin^2(2x^3+2x^2) is sin(2(2x^2+2x^3))(4x+6x^2)

What is the first derivative of sin^2(2x^3+2x^2) ?

The first derivative of sin^2(2x^3+2x^2) is sin(2(2x^2+2x^3))(4x+6x^2)

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\frac{d}{d x} (sin^{2} (2 x^{3} + 2 x^{2}))

sin (2 (2 x^{2} + 2 x^{3})) (4 x + 6 x^{2})

Solution steps

\frac{d}{d x} (sin^{2} (2 x^{3} + 2 x^{2}))

Apply the chain rule:

2 sin (2 x^{3} + 2 x^{2}) \frac{d}{d x} (sin (2 x^{3} + 2 x^{2}))

= 2 sin (2 x^{3} + 2 x^{2}) \frac{d}{d x} (sin (2 x^{3} + 2 x^{2}))

\frac{d}{d x} (sin (2 x^{3} + 2 x^{2})) = cos (2 x^{3} + 2 x^{2}) (6 x^{2} + 4 x)

= 2 sin (2 x^{3} + 2 x^{2}) cos (2 x^{3} + 2 x^{2}) (6 x^{2} + 4 x)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= sin (2 (2 x^{2} + 2 x^{3})) (4 x + 6 x^{2})

\frac{d}{d x} (x^{2} - 7 x + 10)

\frac{\partial}{\partial x} (ln (5 x + y^{3}))

\frac{d y}{d x} = y (1 - 0.0008 y)

\int \frac{x ^{3} + 4}{x + 2} d x

\int \frac{1 - x}{x} d x

What is the derivative of sin^2(2x^3+2x^2) ?
The derivative of sin^2(2x^3+2x^2) is sin(2(2x^2+2x^3))(4x+6x^2)
What is the first derivative of sin^2(2x^3+2x^2) ?
The first derivative of sin^2(2x^3+2x^2) is sin(2(2x^2+2x^3))(4x+6x^2)