What is the d/(dh)((n^2h^2)/(8mL^2)) ?

The d/(dh)((n^2h^2)/(8mL^2)) is (n^2h)/(4L^2m)

What is the first d/(dh)((n^2h^2)/(8mL^2)) ?

The first d/(dh)((n^2h^2)/(8mL^2)) is (n^2h)/(4L^2m)

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\frac{d}{d h} (\frac{n ^{2} h ^{2}}{8 m L ^{2}})

\frac{n ^{2} h}{4 L ^{2} m}

Solution steps

\frac{d}{d h} (\frac{n ^{2} h ^{2}}{8 m L ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{n ^{2}}{8 m L ^{2}} \frac{d}{d h} (h^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{n ^{2}}{8 m L ^{2}} \cdot 2 h^{2 - 1}

Simplify

\frac{n ^{2}}{8 m L ^{2}} \cdot 2 h^{2 - 1} : \frac{n ^{2} h}{4 L ^{2} m}

= \frac{n ^{2} h}{4 L ^{2} m}

t^{2} y^{^{''}} + 19 t y^{^{'}} + 145 y = 0

\int \frac{x}{x ^{2} + 8} d x

\frac{d}{d x} (x^{8} arctan (x^{3}))

y^{^{'}} = k (y - 70)

\int \frac{ln ( 8 x )}{x} d x

What is the d/(dh)((n^2h^2)/(8mL^2)) ?
The d/(dh)((n^2h^2)/(8mL^2)) is (n^2h)/(4L^2m)
What is the first d/(dh)((n^2h^2)/(8mL^2)) ?
The first d/(dh)((n^2h^2)/(8mL^2)) is (n^2h)/(4L^2m)