What is the solution for 12x^2y+y^'=-2x^2 ?

The solution for 12x^2y+y^'=-2x^2 is y=(e^{-4x^3+c_{1}})/6-1/6

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12x^2y+y^'=-2x^2

12 x^{2} y + y^{^{'}} = - 2 x^{2}

y = \frac{e ^{- 4 x^{3} + c_{1}}}{6} - \frac{1}{6}

Solution steps

12 x^{2} y + y^{'} (x) = - 2 x^{2}

Solve separable ODE:

y = \frac{e ^{- 4 x^{3} + c_{1}}}{6} - \frac{1}{6}

y = \frac{e ^{- 4 x^{3} + c_{1}}}{6} - \frac{1}{6}

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\frac{d}{d x} (\frac{x - x ^{2}}{x - 1})

\frac{d y}{d x} = 2 y x

\int \frac{2 ^{t}}{2 ^{t} + 3} d t

What is the solution for 12x^2y+y^'=-2x^2 ?
The solution for 12x^2y+y^'=-2x^2 is y=(e^{-4x^3+c_{1}})/6-1/6