What is the integral of-1/(sqrt(1-x^2)) ?

The integral of-1/(sqrt(1-x^2)) is -arcsin(x)+C

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integral of-1/(sqrt(1-x^2))

\int - \frac{1}{1 - x ^{2}} d x

- arcsin (x) + C

Solution steps

\int - \frac{1}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= - arcsin (x)

Add a constant to the solution

= - arcsin (x) + C

x \to 0 - lim (\frac{x ^{2}}{x})

\int e^{5 x} d x

\int \frac{x ^{2}}{x + 1} d x

x y^{^{'}} + y = - 7 x y^{2}

\int (x^{2} - 1) 2 x + 1 d x

What is the integral of-1/(sqrt(1-x^2)) ?
The integral of-1/(sqrt(1-x^2)) is -arcsin(x)+C