What is the integral from pi/9 to infinity of 2/x ?

The integral from pi/9 to infinity of 2/x is diverges

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integral from pi/9 to infinity of 2/x

\int_{\frac{π}{9}}^{\infty} \frac{2}{x} d x

diverges

Solution steps

\int_{\frac{π}{9}}^{\infty} \frac{2}{x} d x

Compute the indefinite integral:

\int \frac{2}{x} d x = 2 ln ∣ x ∣ + C

Compute the boundaries:

\int_{\frac{π}{9}}^{\infty} \frac{2}{x} d x =

diverges

= diverges

n = 2 \sum \infty \frac{5}{7 ^{n}}

\frac{\partial}{\partial y} (4 x^{2} y^{3})

\frac{\partial}{\partial x} (ln (x))

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{e ^{x}})

\frac{d y}{d x} = x^{4} y^{- 5}

What is the integral from pi/9 to infinity of 2/x ?
The integral from pi/9 to infinity of 2/x is diverges