What is (\partial)/(\partial x)(2y-2yx) ?

The answer to (\partial)/(\partial x)(2y-2yx) is -2y

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(\partial)/(\partial x)(2y-2yx)

\frac{\partial}{\partial x} (2 y - 2 y x)

- 2 y

Solution steps

\frac{\partial}{\partial x} (2 y - 2 y x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (2 y x)

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (2 y x) = 2 y

= 0 - 2 y

Simplify

= - 2 y

\frac{d}{d x} (3 ln (sin (x)))

\frac{d ^{2}}{d t ^{2}} (- 9.8 t^{2} + 2 t + 1)

y^{^{'}} = \frac{3 x ^{2} + 4 x - 4}{2 y - 4}, y (1) = 3

(x + 8)^{2}

\frac{d}{d x} (6 sin (x) + 6 cos (x))

What is (\partial)/(\partial x)(2y-2yx) ?
The answer to (\partial)/(\partial x)(2y-2yx) is -2y