What is the integral of (10)/(x^4) ?

The integral of (10)/(x^4) is -(10)/(3x^3)+C

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integral of (10)/(x^4)

\int \frac{10}{x ^{4}} d x

- \frac{10}{3 x ^{3}} + C

Solution steps

\int \frac{10}{x ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{x ^{4}} d x

Apply the Power Rule

: - \frac{1}{3 x ^{3}}

= 10 (- \frac{1}{3 x ^{3}})

Simplify

10 (- \frac{1}{3 x ^{3}}) : - \frac{10}{3 x ^{3}}

= - \frac{10}{3 x ^{3}}

Add a constant to the solution

= - \frac{10}{3 x ^{3}} + C

\int \frac{6 x ^{2} + 2 x - 1}{3 x ^{2}} d x

\frac{d}{d x} (\frac{y}{x ^{2} + y ^{2} + 1})

f (x) = x^{2} e^{4 x}

\frac{d}{d x} (ln (x) sec (x))

\frac{d y}{d x} = 3 x^{2} - x y

What is the integral of (10)/(x^4) ?
The integral of (10)/(x^4) is -(10)/(3x^3)+C