What is the derivative of 4/3 x^3-4x^2-60x+10 ?

The derivative of 4/3 x^3-4x^2-60x+10 is 4x^2-8x-60

What is the first derivative of 4/3 x^3-4x^2-60x+10 ?

The first derivative of 4/3 x^3-4x^2-60x+10 is 4x^2-8x-60

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\frac{d}{d x} (\frac{4}{3} x^{3} - 4 x^{2} - 60 x + 10)

4 x^{2} - 8 x - 60

Solution steps

\frac{d}{d x} (\frac{4}{3} x^{3} - 4 x^{2} - 60 x + 10)

Simplify

\frac{4}{3} x^{3} - 4 x^{2} - 60 x + 10 : \frac{4 x ^{3}}{3} - 4 x^{2} - 60 x + 10

= \frac{d}{d x} (\frac{4 x ^{3}}{3} - 4 x^{2} - 60 x + 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{4 x ^{3}}{3}) - \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (60 x) + \frac{d}{d x} (10)

\frac{d}{d x} (\frac{4 x ^{3}}{3}) = 4 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (60 x) = 60

\frac{d}{d x} (10) = 0

= 4 x^{2} - 8 x - 60 + 0

Simplify

= 4 x^{2} - 8 x - 60

x^{\frac{1}{4}}, 2 - x, 0

y = 3 e^{x}

f (x) = x^{3} - 3 x^{2} + 1, at x = 2

\int \frac{ln ( ln ( x ) )}{x} d x

\int_{0}^{5 π} x^{3} sin (x) d x

What is the derivative of 4/3 x^3-4x^2-60x+10 ?
The derivative of 4/3 x^3-4x^2-60x+10 is 4x^2-8x-60
What is the first derivative of 4/3 x^3-4x^2-60x+10 ?
The first derivative of 4/3 x^3-4x^2-60x+10 is 4x^2-8x-60