What is the integral of (x^2+3)^2 ?

The integral of (x^2+3)^2 is (x^5)/5+2x^3+9x+C

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integral of (x^2+3)^2

\int (x^{2} + 3)^{2} d x

\frac{x ^{5}}{5} + 2 x^{3} + 9 x + C

Solution steps

\int (x^{2} + 3)^{2} d x

Expand

(x^{2} + 3)^{2} : x^{4} + 6 x^{2} + 9

= \int x^{4} + 6 x^{2} + 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{4} d x + \int 6 x^{2} d x + \int 9 d x

\int x^{4} d x = \frac{x ^{5}}{5}

\int 6 x^{2} d x = 2 x^{3}

\int 9 d x = 9 x

= \frac{x ^{5}}{5} + 2 x^{3} + 9 x

Add a constant to the solution

= \frac{x ^{5}}{5} + 2 x^{3} + 9 x + C

6 x^{\frac{2}{3}}

\int e^{- 5 r} d r

y = e^{2 x - x^{2}}

\frac{d y}{d x} = \frac{8 x}{7 y}

x \to - \infty lim (\frac{0}{x})

What is the integral of (x^2+3)^2 ?
The integral of (x^2+3)^2 is (x^5)/5+2x^3+9x+C