What is the solution for 3(dy)/(dx)=e^{y-6x} ?

The solution for 3(dy)/(dx)=e^{y-6x} is y=-ln((e^{-6x})/(18)-c_{1})

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3(dy)/(dx)=e^{y-6x}

3 \frac{d y}{d x} = e^{y - 6 x}

y = - ln (\frac{e ^{- 6 x}}{18} - c_{1})

Solution steps

3 \frac{d y}{d x} = e^{y - 6 x}

Solve separable ODE:

y = - ln (\frac{e ^{- 6 x}}{18} - c_{1})

y = - ln (\frac{e ^{- 6 x}}{18} - c_{1})

\frac{d}{d x} (2 (2 x e^{2 x} + e^{2 x} \cdot 2 x^{2}))

x \to - 2 lim (\frac{x}{( x + 2 ) ^{3}})

\int x sec (x^{2}) tan (x^{2}) d x

f (x) = \frac{2 x ^{3} - 4 x ^{2} + 3}{x}

\frac{\partial}{\partial y} (e^{x} tan (y))

What is the solution for 3(dy)/(dx)=e^{y-6x} ?
The solution for 3(dy)/(dx)=e^{y-6x} is y=-ln((e^{-6x})/(18)-c_{1})