What is the integral of x^2-sqrt(x) ?

The integral of x^2-sqrt(x) is (x^3)/3-2/3 x^{3/2}+C

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integral of x^2-sqrt(x)

\int x^{2} - x d x

\frac{x ^{3}}{3} - \frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int x^{2} - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int x d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

= \frac{x ^{3}}{3} - \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{x ^{3}}{3} - \frac{2}{3} x^{\frac{3}{2}} + C

x \to + 0 lim (9 x - 4)

x \to - 1 - lim (2)

\int sin^{2} (2 t) cos^{3} (2 t) d t

f (x) = x^{2} - 2, at x = 4

f (x) = ln (x + ln (x))

What is the integral of x^2-sqrt(x) ?
The integral of x^2-sqrt(x) is (x^3)/3-2/3 x^{3/2}+C