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Popular >

integral of y^{-1}

Solution

\int y^{- 1} d y

Solution

ln ∣ y ∣ + C

Solution steps

\int y^{- 1} d y

Use the common integral:

\int y^{- 1} d y = ln (∣ y ∣)

= ln ∣ y ∣

Add a constant to the solution

= ln ∣ y ∣ + C

Popular Examples

integral from-1 to 1 of x^2-x^4

\int_{- 1}^{1} x^{2} - x^{4} d x

derivative of 4(e^x^9)

\frac{d}{d x} (4 (e^{x})^{9})

(\partial)/(\partial x)(zln(xy))

\frac{\partial}{\partial x} (z ln (x y))

inverse oflaplace (s+2)/((s+1)(s-s^2))inverse laplace

\frac{s + 2}{( s + 1 ) ( s - s ^{2} )}

integral of (8x^2-4x+7)/(4x^3+x^2+4x+1)

\int \frac{8 x ^{2} - 4 x + 7}{4 x ^{3} + x ^{2} + 4 x + 1} d x

Frequently Asked Questions (FAQ)

What is the integral of y^{-1} ?
The integral of y^{-1} is ln|y|+C