What is the derivative of (x^2-36/(x+6)) ?

The derivative of (x^2-36/(x+6)) is 1

What is the first derivative of (x^2-36/(x+6)) ?

The first derivative of (x^2-36/(x+6)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 36}{x + 6})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 36}{x + 6})

Simplify

\frac{x ^{2} - 36}{x + 6} : x - 6

= \frac{d}{d x} (x - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (6)

\frac{d x}{d x} = 1

\frac{d}{d x} (6) = 0

= 1 - 0

Simplify

= 1

\frac{d}{d x} (3^{x + 10})

f (x) = 2 sin (2 x)

\int \frac{1}{x ( x + 2 )} d x

(2 y + 2 t - 7) d t + (4 y + 2 t - 1) d y = 0

\frac{\partial}{\partial u} (tan (5 u v^{5}))

What is the derivative of (x^2-36/(x+6)) ?
The derivative of (x^2-36/(x+6)) is 1
What is the first derivative of (x^2-36/(x+6)) ?
The first derivative of (x^2-36/(x+6)) is 1