What is the integral from 1 to 9 of x^2 ?

The integral from 1 to 9 of x^2 is 728/3

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integral from 1 to 9 of x^2

\int_{1}^{9} x^{2} d x

\frac{728}{3}

Decimal

242.66666 \dots

Solution steps

\int_{1}^{9} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{9}

= [\frac{x ^{3}}{3}]_{1}^{9}

Compute the boundaries:

\frac{728}{3}

= \frac{728}{3}

\frac{x ^{2} + 3 x}{6}

\int 6 cos^{4} (x) d x

\int \frac{x}{x ^{2} - 3} d x

f (k) k e^{- 3 k}

y = x^{3 s i n (x)}

What is the integral from 1 to 9 of x^2 ?
The integral from 1 to 9 of x^2 is 728/3