What is the tangent of f(x)=x^4-25x^2+144,\at x=2 ?

The tangent of f(x)=x^4-25x^2+144,\at x=2 is y=-68x+196

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tangent of f(x)=x^4-25x^2+144,\at x=2

tangent of

f (x) = x^{4} - 25 x^{2} + 144, at x = 2

y = - 68 x + 196

Solution steps

Find the tangent point:

(2, 60)

Find the slope of

f (x) = x^{4} - 25 x^{2} + 144 : \frac{df ( x )}{d x} = 4 x^{3} - 50 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 68

Find the line with slope m=

- 68

and passing through

(2, 60) : y = - 68 x + 196

y = - 68 x + 196

\int_{0}^{4} (4 - x)^{2} d x

y^{^{''}} - (\frac{2}{x}) y^{^{'}} - (\frac{3}{x ^{2}}) y = 0

n = 0 \sum \infty cos (2 n)

r \to 1 lim (\frac{8 r + 1}{r + 3})

\int x sin^{3} (x) d x

What is the tangent of f(x)=x^4-25x^2+144,\at x=2 ?
The tangent of f(x)=x^4-25x^2+144,\at x=2 is y=-68x+196