What is the derivative of 4x^3-48x^2+6x+4 ?

The derivative of 4x^3-48x^2+6x+4 is 12x^2-96x+6

What is the first derivative of 4x^3-48x^2+6x+4 ?

The first derivative of 4x^3-48x^2+6x+4 is 12x^2-96x+6

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derivative of

4 x^{3} - 48 x^{2} + 6 x + 4

12 x^{2} - 96 x + 6

Solution steps

\frac{d}{d x} (4 x^{3} - 48 x^{2} + 6 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (48 x^{2}) + \frac{d}{d x} (6 x) + \frac{d}{d x} (4)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (48 x^{2}) = 96 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (4) = 0

= 12 x^{2} - 96 x + 6 + 0

Simplify

= 12 x^{2} - 96 x + 6

e^{x} \frac{d y}{d x} + x y^{2} = 0

\int cos (x^{2} + 1) d x

y = x, 5 y = x + 6

\frac{d y}{d x} = \frac{4 y}{3 x}

\int \frac{1}{x ^{2} + 6 x + 5} d x

What is the derivative of 4x^3-48x^2+6x+4 ?
The derivative of 4x^3-48x^2+6x+4 is 12x^2-96x+6
What is the first derivative of 4x^3-48x^2+6x+4 ?
The first derivative of 4x^3-48x^2+6x+4 is 12x^2-96x+6