ty^'-2y=t^4

Lösung

t y^{^{'}} - 2 y = t^{4}

y = \frac{t ^{4}}{2} + c_{1} t^{2}

Schritte zur Lösung

t y^{'} (t) - 2 y = t^{4}

Solve linear ODE:

y = \frac{t ^{4}}{2} + c_{1} t^{2}

y = \frac{t ^{4}}{2} + c_{1} t^{2}

\int_{0}^{1} sin (x) e^{x} d x

in v erse l a pl a ce \frac{1}{s} - \frac{s + 8}{s ^{2} + 8 s + 25}

\int ∣ x - 3 ∣ d x

d er i v a t i v e f (x) = (\frac{x + 2}{x - 2})^{5}

d er i v a t i v e f (x) = x^{2} 1 - x^{2}